C++ 开发之实现操作符重载的实例

main.c

#include "iostream" 
#include "Matrix.h" 
using namespace std; 
int main(){ 
  int row1,row2,col1,col2; 
  cout << "请输入第一个矩阵的行和列:n"; 
  cin >> row1 >> col1; 
  Matrix m1(row1,col1); 
  cout << "请输入" << row1 << '*' << col1 << "个数:n"; 
  cin >> m1; 
  cout << "输出矩阵的值:n"; 
  cout << m1; 
  cout << "请输入第二个矩阵的行和列:n"; 
  cin >> row2 >> col2; 
  Matrix m2(row2,col2); 
  cout << "请输入" << row2 << '*' << col2 << "个数:n "; 
  cin >> m2; 
  cout << "输出矩阵的值:n"; 
  cout << m2; 
  if (col1 != row2) 
    cout << "这两个矩阵无法相乘n"; 
  else 
  { 
    cout << "判断矩阵m1与m2是否相等：n"; 
    if (m1==m2) 
    { 
      cout << "m1和m2相等：n"; 
    } 
    else 
    { 
      cout << "m1和m2不相等：n"; 
    } 
 
    cout << "m1拷贝构造m3矩阵结果输出：n"; 
    Matrix m3(m1); 
    cout << m3; 
 
    cout << "m1赋值重载m4矩阵结果输出：n"; 
    Matrix m4(m1.Row,m1.Column); 
    m4 = m1; 
    cout << m4; 
 
    cout << "m1*m2矩阵相乘输出m5：n"; 
    Matrix m5(m1.Row,m2.Column); 
    m5 = m1*m2; 
    cout << m5; 
 
    cout << "矩阵m1*2输出m6：n"; 
    Matrix m6(m1.Row,m1.Column); 
    m6 = m1*2; 
    cout << m6; 
 
    cout << "矩阵m1*0.5输出m7：n"; 
    Matrix m7(m1.Row,m1.Column); 
    m7 = m1 * 0.5; 
    cout << m7; 
 
    cout << "m1*m2矩阵相乘输出m1：n"; 
    m1 *= m2; 
    cout << m1; 
 
    cout << "m1矩阵前自增输出n"; 
    cout << ++m1; 
 
    cout << "m1矩阵后自增输出n"; 
    cout << m1++; 
 
    cout << "m1矩阵输出n"; 
    cout << m1; 
 
    cout << "m1矩阵前自减输出n"; 
    cout << --m1; 
 
    cout << "m1矩阵后自减输出n"; 
    cout << m1--; 
 
    cout << "m1矩阵输出n"; 
    cout << m1; 
  } 
  return 0; 
} 

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